5r^2-9r+1=0

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Solution for 5r^2-9r+1=0 equation: 



5r^2-9r+1=0

a = 5; b = -9; c = +1;
Δ = b2-4ac
Δ = -92-4·5·1
Δ = 61
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{61}}{2*5}=\frac{9-\sqrt{61}}{10}
$


$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{61}}{2*5}=\frac{9+\sqrt{61}}{10}
$

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